Boiler Operation Engineer (BOE) Exam

Numerical problems from BOE exams

Boiler drawing questions from BOE exams 

MCQ and Short Answer Questions 

Boiler Acts and Rules 

Steam Properties

Fuel Combustion

Boiler Operation and Performance

Boiler Mountings and Accessories

Boiler Material

Boiler Feedwater Chemistry 

Articles and News

Comments

Post a Comment

Popular posts from this blog

Solved Numerical Problems from Boiler Operation Engineer Exams

Image
Boiler Mechanics Problem (Jharkhand BOE 2024) A solid round bar 3 m long 5cm in diameter is used as a strut with both ends hinged. Determine the crippling load. Take E=2 x 10 5 N/mm 2 .  Solution Moment of inertia \(I = \frac{\pi }{{64}}x{5^4} = 30.68\,c{m^4} = 30.68x{10^4}\,m{m^4}\)                         Both ends of the bar are hinged. Crippling load for this condition is \(P = \frac{{{\pi ^2}EI}}{{{l^2}}} = \frac{{{\pi ^2}x2x{{10}^5}x30.68x{{10}^4}}}{{{{3000}^2}}}\)                           = 67288 N = 67.288 kN These questions are taken from study material for  Boiler Operation Engineer Exam by amiestudycircle.com .  Problem (Jharkhand BOE 2022, 3 marks) A hollow shaft is to transmit 300 kW at 80rpm. If shear stress is not to exceed 60 N/mm 2 a diameter is 0.6 of the external diameter, find external and internal ...
Read more

Geotechnical & Foundation Engineering (Solved Numerical Problems)

Image
Numerical A 1000 cc core cutter weighing 946.80 g was used to find out the in-situ unit weight of an embankment. The weight of the core cutter filled with soil was noted to be 2770.60 g. Laboratory tests on the sample indicated a water content of 10.45 % and specific gravity of solids of 2.65. Determine the bulk unit weight, dry unit weight, void ratio, and degree of saturation of the sample. (AMIE Summer 2023, 8 marks) Solution Weight of soil in core cutter = 2770.60 - 946.80 = 1823.8 g Bulk unit weight, γ t = W/V = 1823.8/1000 = 1.82 g/ccDry unit weight, γ d = γ t /(1 + w) = 1.82/(1 + 0.1045) = 1.65 g/cc Void ratio, e = (G s γ w /γ d ) - 1 = (2.65 x 1.0/1.65) - 1 = 0.61 Degree of saturation, S = wG s /e = (0.1045 x 2.65)/0.61 = 0.4540 = 45.4% Numerical What is the theoretical height of the capillary rise and the capillary pressure in fine-grained soil with an effective size (D 10 ) of 0.002 mm? (AMIE Summer 2023, 4 marks) Solution D 10 = 0.002 mm;  Using the assumption that th...
Read more