Boiler Mechanics Problem (Jharkhand BOE 2024) A solid round bar 3 m long 5cm in diameter is used as a strut with both ends hinged. Determine the crippling load. Take E=2 x 10 5 N/mm 2 . (Jharkhand BOE 2024) Solution Moment of inertia \(I = \frac{\pi }{{64}}x{5^4} = 30.68\,c{m^4} = 30.68x{10^4}\,m{m^4}\) Both ends of the bar are hinged. Crippling load for this condition is \(P = \frac{{{\pi ^2}EI}}{{{l^2}}} = \frac{{{\pi ^2}x2x{{10}^5}x30.68x{{10}^4}}}{{{{3000}^2}}}\) = 67288 N = 67.288 kN Problem (Jharkhand BOE 2022, 3 marks) A hollow shaft is to transmit 300 kW at 80rpm. If shear stress is not to exceed 60 N/mm 2 a diameter is 0.6 of the external diameter, find external and internal diameters maximum torque is 1.4 times the mean torque. (Jharkhand BOE 2022, 3 marks) Solution ...
AMIE Study Circle Blog
AMIE Exams, BTech for Working Professionals, SSC-JE, GATE, PSU, ESE, Manager Certificate (Mining), Boiler Operation Engineer Exams