Computer Architecture - MCQs from AMIE exams (Summer 2020)

Choose the correct answer for the following (2 x 10)

1. The master clock supplies a constant ⸻ to all parts in a register.
(a) bit
(b) beat
(c) clock pulse
(d) None of the above

2. Binary equivalent of (41.6875)10 is
(a) (101001.1011)2
(b) (101101.1011)2
(c) (101001.1001)2
(d) (101011.1001)2

3. Given a number N in base "r" having n digits, the (r - l)’s complement of N is defined as
(a) (rn - l) - N
(b) N - (rn - l)
(c) rn - (N - 1)
(d) (r - l) - Nn

4. A number of storage registers connected to a common operational unit are called
(a) RAM
(b) ROM
(c) ALU
(d) None of the above

5. Which of the following is not an addressing mode?
(a) Relative address mode
(b) Indexed register addressing mode
(c) Indexed addressing mode
(d) Base register addressing mode

6. Transfer of data under programmed I/O is between
(a) CPU and peripheral
(b) CPU and memory
(c) ALU and peripheral
(d) ALU and memory

7. The excess three codes of decimal number 7 is
(a) 1100
(d) 0000
(c) 1010
(d) None of the above

8. The storage capacity of the optical Disk is determined using
(a) Number of recording surfaces, number of tracks per surface, number of sectors per track
(b) Number of tracks on a disk
(c) Number of sectors and bytes per sector
(d) Number of recording surfaces, number of tracks per surface, number of sectors per track and number of bytes per sector

9. The microprogrammed control unit is
(a) potentially faster than hardwired
(b) linked to the introduction of low cost and high-density memory chips
(c) much more flexible
(d) All of the above

10. An arithmetic shift-right is equivalent to
(a) multiplying the number by 2
(b) dividing the number by 2
(c) changing the sign of the number
(d) reversing the number

Answer

1. (c) Synchronous digital systems have a master clock generator that supplies a continuous train of clock pulses.

2. (a) 

Steps to Convert to Binary
41 ÷ 2 = 20 R 1
20 ÷ 2 = 10 R 0
10 ÷ 2 = 5 R 0
5 ÷ 2 = 2 R 1
2 ÷ 2 = 1 R 0
1 ÷ 2 = 0 R 1

0.6875 × 2 = 0.375 + 1
0.375 × 2 = 0.75 + 0
0.75 × 2 = 0.5 + 1
0.5 × 2 = 0 + 1

Reading the remainders from the whole portion from the bottom up and the fractional portion from the top down:
101001.1011

3. (a) 

4. (c)  Instead of having individual registers performing the microoperations directly, computer systems. employ a number of storage registers connected to a common operational unit called an. arithmetic logic unit abbreviated ALU.

5. (a)

6. (a) Programmed I/O instructions are the result of I/O instructions written in a computer program. Each data item transfer is initiated by the instruction in the program. Usually, the program controls data transfer to and from the CPU and peripheral.

7. (c)  For getting an excess 3 codes, add +3 to the number

7 + 3 = 10

10 In binary is (1010)2

Hence excess 3 code for 7 is (1010)2

8. (d) Capacity of the disk pack = Total number of surfaces x Number of tracks per surface x Number of sectors per track x Number of bytes per sector

9. (c)

10. (b) Arithmetic shifts can be useful as efficient ways to perform multiplication or division of signed integers by powers of two. Shifting left by n bits on a signed or unsigned binary number has the effect of multiplying it by 2n. Shifting right by n bits on a two's complement signed binary number has the effect of dividing it by 2n.

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