Skip to main content

Pulse and Digital Circuits (Short Answer Questions)

Differentiate vectored and non-vectored interrupts.

Interrupts may be vectored or non-vectored, depending upon the provision of their pre-defined branching address. If the branching address of the interrupt, where its ISR to be located, is pre-defined, then the interrupt is designated as a vectored interrupt. On the other hand, if the interrupt is not assigned any such pre-defined branching address for its ISR, it would be taken as a non-vectored interrupt.

List the advantage of segmented memory.

  • An immediate advantage of having separate data and code segments is that one program can work on several sets of data.
  • Perhaps the greatest advantage of segmented memory is that programs that reference logical addresses only can be loaded and run anywhere in memory.Explain importance of Hit ratio.

Explain the locality of reference.

Locality of Reference. The characteristics of a typical program that leads to a predictable access pattern is referred to as the locality of reference. 

What is a bootstrap loader?

The bootstrap loader is a small program whose single function is to load the OS into the memory and allows it to begin operation.

Explain about auxiliary memory in memory organization.

Auxiliary memory is also called secondary memory unit or mass storage system. As the name implies, the mass storage system has the capacity to store large amount of data without any electrical power. But its speed is slower than the main memory or semiconductor memory. Normally it stores the data and program which is not used by CPU at that point of time. The information from auxiliary memory will be transferred to the main semiconductor memory whenever the data or program is required by the CPU. The common examples of auxiliary memory devices are magnetic disk, magnetic tape, and compact disk. 

Explain content addressable memory.

It is a special purpose random access memory that performs association operation in addition to read and write operation. 

How many lines of address bus must be used to access 4096 bytes of memory?

\(\begin{array}{l}4096 = {2^{12}}\\{\log _2}(4096) = 12\end{array}\)

Thus, 12 address lines are needed to access 4096 bytes of memory. 

Write the importance of cache memory.

Cache memory is a very high speed semiconductor memory which can speed up the CPU.
It acts as a buffer between the CPU and the main memory. It is used to hold those parts of
data and program which are most frequently used by the CPU. 

Differentiate isolated I/O and Memory mapped I/O.

Numerous computers transfer data between the CPU and memory or I/O via a single bus. In an isolated I/O arrangement, the CPU has separate instructions for input and output, each of which is associated with an address in an interface register. To ensure that assignment of interface addresses does not impact the values of memory addresses, the isolated I/O approach divides both memory and I/O addresses, as each interface address space is independent. The other option is to use the same address space for I/O and memory.

---


The study material for AMIE/BTech/Junior Engineer exams is available at https://amiestudycircle.com

Comments

Popular posts from this blog

Mechanics of Fluids (Solved Numerical Problems)

Numerical The surface Tension of water in contact with air at 20°C is 0.0725 N/m. The pressure inside a droplet of water is to be 0.02 N/cm² greater than the outside pressure. Calculate the diameter of the droplet of water. (7 marks) (AMIE Summer 2023) Solution Surface tension, σ = 0.0725 N/m Pressure intensity, P = 0.02 N/m 2 P = 4σ/d Hence, the Diameter of the dropd = 4 x 0.0725/200 = 1.45 mm Numerical Find the surface tension in a soap bubble of 40 mm diameter when the inside pressure is 2.5 N/m² above atmospheric pressure. (7 marks) (AMIE Summer 2023) Answer: 0.0125 N/m Numerical The pressure outside the droplet of water of diameter 0.04 mm is 10.32 N/cm² (atmospheric pressure). Calculate the pressure within the droplet if surface tension is given as 0.0725 N/m of water. (AMIE Summer 2023, 7 marks) Answer: 0.725 N/cm 2   Numerical An open lank contains water up to a depth of 2 m and above it an oil of specific gravity 0.9 for a depth of 1 m. Find the pressure intensity (i) at t...

Energy Systems (Solved Numerical Problems)

Wind at 1 standard atmospheric pressure and \({15^0}C\) has velocity of 15 m/s, calculate (i) the total power density in the wind stream (ii) the maximum obtainable power density (iii) a reasonably obtainable power density (iv) total power (v) torque and axial thrust Given: turbine diameter = 120 m, and turbine operating speed = 40 rpm at maximum efficiency. Propeller type wind turbine is considered. (AMIE Winter 2023) Solution For air, the value of gas constant is R = 0.287 kJ/kg.K 1 atm = 1.01325 x 105 Pa Air density \(\rho  = \frac{P}{{RT}} = \frac{{1.01325x{{10}^5}}}{{287}}(288) = 1.226\,kg/{m^3}\) Total Power \({P_{total}} = \rho A{V_1}^3/2\) Power density \(\begin{array}{l}\frac{{{P_{total}}}}{A} = \frac{1}{2}\rho {V_1}^3\\ = \frac{1}{2}(1.226){(15)^3}\\ = 2068.87{\mkern 1mu} W/{m^2}\end{array}\) Maximum power density \(\begin{array}{l}\frac{{{P_{\max }}}}{A} = \frac{8}{{27}}\rho A{V^3}_1\\ = \frac{8}{{27}}(1.226){(15)^3}\\ = 1226{\mkern 1mu} W/{m^2}\end{array}\) Assuming eff...

Design of Electrical Systems (Solved Numerical Problems)

Important note There is something wrong with this question paper. It seems that instead of "Design of Electrical Systems" the IEI has given problems from "Electrical Machines". You should raise a complaint to director_eea@ieindia.org in this regard. Numerical A 120 V DC shunt motor draws a current of 200A. The armature resistance is 0.02 ohms and the shunt field resistance is 30 ohms. Find back emf. If the lap wound armature has 90 slots with 4 conductors per slots, at what speed will the motor run when flux per pole is 0.04 Wb?​ (AMIE Summer 2023, 8 marks) Solution The back EMF (E b ) of a DC motor can be calculated using the formula: E b = V - I a R a   Given: V = 120 V I a = 200 A R a = 0.02 ohms Substituting the values into the formula: E b = 120 − 200 × 0.02 = 120 − 4​ = 116 V Now, let's calculate the speed (N) at which the motor will run using the given flux per pole (φ p ). The formula to calculate the speed of a DC motor is: N = 60×E b /(P×φ p ) Wh...