A steam table gives the properties of water (liquid, vapor, and mixture) at different temperatures and pressures. Common properties listed:
T = Temperature
P = Pressure (absolute, not gauge)
v = Specific volume (m³/kg)
u = Internal energy (kJ/kg)
h = Enthalpy (kJ/kg)
s = Entropy (kJ/kg·K)
x = Quality (mass fraction of vapor, 0 = sat liquid, 1 = sat vapor)
Understand Column Symbols
Every column represents a distinct property or baseline state:
Subscript f (vf,hf): Properties of saturated liquid (100% liquid water).
Subscript g (vg, hg): Properties of saturated vapor (100% dry steam).
Subscript fg (hfg): The latent change during evaporation (hfg = hg - hf)
Identify Your Region
Water can be in three zones:
Compressed (subcooled) liquid – Not about to boil, below saturation temp at given pressure.
Saturated mixture – Liquid and vapor coexist (boiling).
Superheated vapor – Above saturation temperature at given pressure.
Which Table to Use?
Saturated Table (Temperature-Based): Best used when the given variable is a specific temperature.
Saturated Table (Pressure-Based): Best used when the given variable is a specific pressure.
Superheated Steam Table: Used when system temperature exceeds the saturation boiling temperature for its pressure.
Compressed Liquid Table: Used when system pressure exceeds the saturation pressure for its temperature.
Determine Mixture Qualities
If the system is a mixture of liquid and steam, you must use steam quality (x), which is the mass percentage of vapor ranging from 0 to 1.
Calculate mixed properties with this fundamental equation:
v = vf + x (vg - vf)
Apply Linear Interpolation
If your exact system parameters fall between two listed rows, you must execute a vertical linear interpolation to isolate the true midpoint value,
y = y1 + [(x - x1)/(x2 - x1)] x (y2 - y1)
Example (Saturated mixture)
Find the specific enthalpy (h) of a wet steam mixture at a pressure of 10 bar with a steam quality (x) of 0.85.
Open the Saturated Steam Pressure Table
Locate the 10 bar row.
Extract baseline values:
hf = 762.6 kJ/kg
hfg = 2014.6 kJ/kg
Compute final mixture value:
h = 762.6 + 0.85 x (2014.6) = 2475.01 kJ/kg
Example (Superheated steam)
Find the specific volume (u) of steam at 10 bar and 300°C.
- Check the saturated table for 10 bar to find the boiling boundary (Tsat = 179.90 C).
- Because your target 3000 C > 179.90 C, flip over to the Superheated Steam Table.
- Locate the sub-block labeled P= 1.0 MPa (10 bar).
- Read down to the T = 3000 C row, and isolate the value under the u column (v = 0.258 m3/kg).
Example
- Find the enthalpy of water at P = 0.5 MPa, T = 200°C.
- Find saturation temperature at 0.5 MPa from saturation table (Pressure entry) at 0.5 MPa ≈ 151.8°C.
- Compare: T (200°C) > 151.8°C → Superheated vapor.
- Go to Superheated steam table at 0.5 MPa.
- Find row for 200°C → read h (enthalpy) ≈ 2855 kJ/kg.
- From sat table at 0.5 MPa: hf = 640 kJ/kg, hg = 2748 kJ/kg.
- Formula: h = hf + x(hg – hf) = 640 + 0.9(2108) = 2537 kJ/kg.
Common Mistakes to Avoid
- Using gauge pressure: Steam tables use absolute pressure (Pabs = Pgauge + Patm).
- Quality outside 0 – 1: If x > 1 → superheated; if x < 0 → compressed liquid. Interpolation required between table entries.
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